Your 200-g cup of tea is boiling-hot. About how much ice should you add to bring it down to a comfortable sipping temperature of 65°C? (Assume that the ice is initially at −15°C. The specific heat capacity of ice is 0.5 cal/g∙°C.)
The equation for latent heat is L=Q/m
Now we need to find the heat lost by the water
There is no heat lost
The ice cube gains heat lost by the water 7000 calories.