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Physics: Principles with Applications | 7th Edition | ISBN: 9780321625922 | Authors: Douglas C. Giancoli
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Solved: A person who is properly restrained by an

Chapter 2, Problem 61GP

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QUESTION: A person who is properly restrained by an over-the-shoulder seat belt has a good chance of surviving a car collision if the deceleration does not exceed 30 “g’s” (\(1.00 \mathrm{~g}=9.80 \mathrm{~m} / \mathrm{s}^{2}\)). Assuming uniform deceleration at 30 g’s, calculate the distance over which the front end of the car must be designed to collapse if a crash brings the car to rest from 95 km/h.

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QUESTION: A person who is properly restrained by an over-the-shoulder seat belt has a good chance of surviving a car collision if the deceleration does not exceed 30 “g’s” (\(1.00 \mathrm{~g}=9.80 \mathrm{~m} / \mathrm{s}^{2}\)). Assuming uniform deceleration at 30 g’s, calculate the distance over which the front end of the car must be designed to collapse if a crash brings the car to rest from 95 km/h.

ANSWER:

Step 1 of 2

Given data:

The deceleration is \(a=-30\ \rm{g}\) where \(1.00\ {\rm{g}} = 9.8\ \rm{m/s}^2\).

The initial velocity u  is 95 km/h.

The final velocity v is 0 m/s (at rest).

Let us first find the numerical value for the deceleration.

\(a =  - 30\,{\rm{g}} \times \frac{{9.8\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}}}{{1.00\;{\rm{g}}}}\\\)

\(a =  - 294\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}\)

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