Solution Found!
A “seconds” pendulum has a period of exactly 2.000 s—each one-way swing takes 1.000 s
Chapter 11, Problem 82GP(choose chapter or problem)
Problem 82GP
A “seconds” pendulum has a period of exactly 2.000 s—each one-way swing takes 1.000 s. (a) What is the length of a seconds pendulum in Austin, Texas, where g = 9.793 m/s2? (b) If the pendulum is moved to Paris, where g = 9.809 m/s2, by how many millimeters must we lengthen the pendulum? (c) What would be the length of a seconds pendulum on the Moon, where g = 1.62 m/s2?
Questions & Answers
QUESTION:
Problem 82GP
A “seconds” pendulum has a period of exactly 2.000 s—each one-way swing takes 1.000 s. (a) What is the length of a seconds pendulum in Austin, Texas, where g = 9.793 m/s2? (b) If the pendulum is moved to Paris, where g = 9.809 m/s2, by how many millimeters must we lengthen the pendulum? (c) What would be the length of a seconds pendulum on the Moon, where g = 1.62 m/s2?
ANSWER:
Solution 82GP
Step 1 of 3
Part a
We are required to calculate the length of the pendulum in Austin, Texas from other values given.
Given:
If the length of the pendulum in Austin is
From the relation,
The length of the pendulum in Austin is 0.9921 m.