Solution Found!
[1 mC = 10–3 C, 1 ?C = 10–6 C, 1 nC = 10–9 C.]A person scuffing her feet on a wool rug
Chapter 16, Problem 8P(choose chapter or problem)
QUESTION:
Problem 8P
[1 mC = 10–3 C, 1 μC = 10–6 C, 1 nC = 10–9 C.]
A person scuffing her feet on a wool rug on a dry day accumulates a net charge of –42 μC. How many excess electrons does she get, and by how much does her mass increase?
Questions & Answers
QUESTION:
Problem 8P
[1 mC = 10–3 C, 1 μC = 10–6 C, 1 nC = 10–9 C.]
A person scuffing her feet on a wool rug on a dry day accumulates a net charge of –42 μC. How many excess electrons does she get, and by how much does her mass increase?
ANSWER:
Solution 8P:
Step 1 of 2:-
The net charge accumulated by the person is , which is equal to .
The charge of 1 single electron is .
By the quantization of charge
So,
.
So, the person gets excess electrons.