CP A 4.78-MeV alpha particle from a 226Ra decay makes a | StudySoup

Textbook Solutions for Sears and Zemansky's University Physics with Modern Physics

Chapter 39 Problem 22E

Question

Problem 22E

CP A 4.78-MeV alpha particle from a 226Ra decay makes a head-on collision with a uranium nucleus. A uranium nucleus has 92 protons. (a) What is the distance of closest approach of the alpha particle to the center of the nucleus? Assume that the uranium nucleus remains at rest and that the distance of closest approach is much greater than the radius of the uranium nucleus. (b) What is the force on the alpha particle at the instant when it is at the distance of closest approach?

Solution

Solution 22E

Step 1

Use the conservation principle to determine the value of distance. Consider this distance to determine the value of force.

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Title Sears and Zemansky's University Physics with Modern Physics 13 
Author Hugh D. Young; Roger A. Freedman; A. Lewis Ford
ISBN 9780321696861

CP A 4.78-MeV alpha particle from a 226Ra decay makes a

Chapter 39 textbook questions

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