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A gas expands from 264 mL to 971 mL at constant

Chapter 6, Problem 1PE

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QUESTION:

A gas expands from \(264 \mathrm{~mL}\) to \(971 \mathrm{~mL}\) at constant temperature. Calculate the work done (in joules) by the gas if it expands (a) against a vacuum and (b) against a constant pressure of \(4.00 \mathrm{~atm}\).

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QUESTION:

A gas expands from \(264 \mathrm{~mL}\) to \(971 \mathrm{~mL}\) at constant temperature. Calculate the work done (in joules) by the gas if it expands (a) against a vacuum and (b) against a constant pressure of \(4.00 \mathrm{~atm}\).

ANSWER:

Here we have to calculate the work done in the following given conditions

The conditions are,

(a) against a vacuum

(b) against a constant pressure of \(4.00 \mathrm{~atm}\)

 

Step 1 of 2

 

Given:

(a) against vacuum

Work done can be calculated as,

\(\begin{aligned}W &=-\int P d V \\&=-P \Delta V \\&=0 \times \Delta V \\&=0\end{aligned}\)

When the gas is expanding against a vacuum, the work would be equal to zero due to the zero external pressure. Thus, the gas does no work to expand.

 

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