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At t = 0 a grinding wheel has an angular velocity of 24.0

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 16E Chapter 9

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 16E

At t = 0 a grinding wheel has an angular velocity of 24.0 rad/s. It has a constant angular acceleration of 30.0 rad/s2 until a circuit breaker trips at t = 2.00 s. From then on, it turns through 432 rad as it coasts to a stop at constant angular acceleration. (a) Through what total angle did the wheel turn between t = 0 and the time it stopped? (b) At what time did it stop? (c) What was its acceleration as it slowed down?

Step-by-Step Solution:

Solution 16E Step 1: Angular velocity = 24.0 rad/s i 2 Angular acceleration = 30.0 rad /s Time t = 2.0 s Angle = 432 rad Consider = t + 1/2 at 2 f i Substitute values we get 2 2 f 24.0 rad /s × 2s + 1/2 × 30.0 rad /s × 2.0 s e = 108 rad Also consider f + it f 24.0 rad /s + 30.0 rad /s × 2.0 s = 84 rad/s f Step 2 : The total angle did the wheel turn between t = 0 and the time it stopped is = 108 rad + 432 rad f f 539 rad The total angle is 539 rad

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Chapter 9, Problem 16E is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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At t = 0 a grinding wheel has an angular velocity of 24.0

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