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Chapter 6, Problem 121P

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QUESTION:

A 46-kg person drinks 500 g of milk, which has a "caloric" value of approximately 3.0 kJ/g. If only 17 percent of the energy in milk is converted to mechanical work, how high (in meters) can the person climb based on this energy intake? (Hint: The work done in ascending is given by mgh, where m is the mass (in kilograms), g the gravitational acceleration \(\left(9.8\ \mathrm{m} / \mathrm{s}^{2}\right)\), and h the height (in meters).]

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QUESTION:

A 46-kg person drinks 500 g of milk, which has a "caloric" value of approximately 3.0 kJ/g. If only 17 percent of the energy in milk is converted to mechanical work, how high (in meters) can the person climb based on this energy intake? (Hint: The work done in ascending is given by mgh, where m is the mass (in kilograms), g the gravitational acceleration \(\left(9.8\ \mathrm{m} / \mathrm{s}^{2}\right)\), and h the height (in meters).]

ANSWER:

Step 1 of 3

Here we have to calculate the height in meters can the person climb based on this energy intake.

 

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