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Solved: At 850°C, CaCO3 undergoes substantial
Chapter 6, Problem 60P(choose chapter or problem)
At \(850^{\circ} \mathrm{C}, \mathrm{CaCO}_{3}\) undergoes substantial decomposition to yield \(\mathrm{CaO}\) and \(\mathrm{CO}_{2}\). Assuming that the \(\Delta H_{\mathrm{f}}^{\circ}\) values of the reactant and products are the same at \(850^{\circ} \mathrm{C}\) as they are at \(25^{\circ} \mathrm{C}\), calculate the enthalpy change (in \(\mathrm{kJ}\) ) if \(66.8 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) are produced in one reaction.
Questions & Answers
QUESTION:
At \(850^{\circ} \mathrm{C}, \mathrm{CaCO}_{3}\) undergoes substantial decomposition to yield \(\mathrm{CaO}\) and \(\mathrm{CO}_{2}\). Assuming that the \(\Delta H_{\mathrm{f}}^{\circ}\) values of the reactant and products are the same at \(850^{\circ} \mathrm{C}\) as they are at \(25^{\circ} \mathrm{C}\), calculate the enthalpy change (in \(\mathrm{kJ}\) ) if \(66.8 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) are produced in one reaction.
ANSWER:Step 1 of 3
Here, we are going to calculate the enthalpy change of \(\mathrm{CO}_{2}\) produced in the reaction.
We know that, the standard enthalpy change of a reaction \(\Delta H_{\text {reaction, is defined as the }}\) difference between the enthalpies of the products and the enthalpies of the reactants.
\(\Delta H_{\text {reaction }}^{0}=\sum n \Delta H_{f}^{0}(\) product \()-\sum n \Delta H_{f}^{o}(\) reactant \()\)
The reaction is given below:
\(\mathrm{CaCO}_{3}(\mathrm{~s}) \rightarrow \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})\)