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Answer: The formulas for the fluorides of the third-period
Chapter 9, Problem 76P(choose chapter or problem)
The formulas for the fluorides of the third-period elements are \(\mathrm{NaF}, \mathrm{MgF}_{2}, \mathrm{AlF}_{3}, \mathrm{SiF}_{4}, \mathrm{PF}_{5}, \mathrm{SF}_{6}\), and \(\mathrm{ClF}_{3}\). Classify these compounds as covalent or ionic.
Questions & Answers
QUESTION:
The formulas for the fluorides of the third-period elements are \(\mathrm{NaF}, \mathrm{MgF}_{2}, \mathrm{AlF}_{3}, \mathrm{SiF}_{4}, \mathrm{PF}_{5}, \mathrm{SF}_{6}\), and \(\mathrm{ClF}_{3}\). Classify these compounds as covalent or ionic.
ANSWER:Step 1 of 7
Here, we are going to classify the given compounds as covalent or ionic.
a) NaF
The electronegativity of Sodium and Fluorine is 0.9 and 4.0 respectively.
The electronegativity difference between Sodium and Fluorine is 3.1, which is above the 2.0 mark.
Therefore, NaF is an ionic compound.