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Four atoms are arbitrarily labeled D, E, F. and G. Their
Chapter 9, Problem 37P(choose chapter or problem)
Four atoms are arbitrarily labeled D, E, F. and G. Their electronegativities are as follows: D = 3.8, E = 3.3, F = 2.8, and G = 1.3. If the atoms of these elements form the molecules DE, DG, EG, and DF. how would you arrange these molecules in order of increasing covalent bond character?
Questions & Answers
QUESTION:
Four atoms are arbitrarily labeled D, E, F. and G. Their electronegativities are as follows: D = 3.8, E = 3.3, F = 2.8, and G = 1.3. If the atoms of these elements form the molecules DE, DG, EG, and DF. how would you arrange these molecules in order of increasing covalent bond character?
ANSWER:Step 1 of 2
Given electronegativity of each atoms
D = 3.8
E = 3.3
F = 2.8
G = 1.3
Also the molecules formed by their combination are given as DE, DG, EG, and DF.
We have to write the molecules in increasing covalent bond character.