Solution Found!
Answer: From the following data, calculate the average
Chapter 9, Problem 69P(choose chapter or problem)
From the following data, calculate the average bond enthalpy for the N—H bond:
\(\mathrm{NH}_{3}(g) \longrightarrow \mathrm{NH}_{2}(g)+\mathrm{H}(g) \Delta H^{\circ} =435 \mathrm{~kJ} / \mathrm{mol}\)
\(\mathrm{NH}_{2}(g) \longrightarrow \mathrm{NH}(g)+\mathrm{H}(g) \Delta H^{\circ} =381 \mathrm{~kJ} / \mathrm{mol}\)
\(\mathrm{NH}(g) \longrightarrow \mathrm{N}(g)+\mathrm{H}(g) \Delta H^{\circ} =360 \mathrm{~kJ} / \mathrm{mol}\)
Questions & Answers
QUESTION:
From the following data, calculate the average bond enthalpy for the N—H bond:
\(\mathrm{NH}_{3}(g) \longrightarrow \mathrm{NH}_{2}(g)+\mathrm{H}(g) \Delta H^{\circ} =435 \mathrm{~kJ} / \mathrm{mol}\)
\(\mathrm{NH}_{2}(g) \longrightarrow \mathrm{NH}(g)+\mathrm{H}(g) \Delta H^{\circ} =381 \mathrm{~kJ} / \mathrm{mol}\)
\(\mathrm{NH}(g) \longrightarrow \mathrm{N}(g)+\mathrm{H}(g) \Delta H^{\circ} =360 \mathrm{~kJ} / \mathrm{mol}\)
ANSWER:Step 1 of 2
We need to find the average bond enthalpy of 
Given
Average bond enthalpy is a measure of the bond strength in a chemical bond.