Solved: In lab, Will burns a 0.6-g peanut beneath 50 g of | StudySoup

Textbook Solutions for Conceptual Physics

Chapter 16 Problem 1P

Question

Problem 1P

In lab, Will burns a 0.6-g peanut beneath 50 g of water, which increases in temperature from 22°C to 50°C. The amount of heat absorbed by the water can be found with the equation Q = cm ∆ T, where Q is the amount of heat, c the specific heat of water, m the mass of water, and ∆ T the change in the water’s temperature.

a. Assuming that 40% of the heat released makes its way to the water, show that the food value of the peanut is 3500 calories, or 3.5 Calories.

b. What is the food value in calories per gram? In Calories per gram?

Solution

Solution 1P

Step 1:

Peanut mass is 0.6 grams.

The mass of water is 50 grams.

The temperature increase is,

                 

The specific heat of water is, .

The heat absorbed by the water is,

                   [where C is the specific heat]

                       .

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full solution

Title Conceptual Physics 11 
Author Paul G. Hewitt
ISBN 9780321568090

Solved: In lab, Will burns a 0.6-g peanut beneath 50 g of

Chapter 16 textbook questions

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