An air-filled rubber ball has a diameter of 6 in. If the air pressure within the ball is increased until the diameter becomes 7 in., determine the average normal strain in the rubber.
Read moreTextbook Solutions for Mechanics of Materials
Chapter 2 Problem 2-34
Question
If the normal strain is defined in reference to the final length \(\Delta s^{\prime}\), that is,
\(\epsilon^{\prime}=\lim _{\Delta s^{\prime} \rightarrow 0}\left(\frac{\Delta s^{\prime}-\Delta s}{\Delta s^{\prime}}\right)\)
instead of in reference to the original length, Eq. 2–2, show that the difference in these strains is represented as a second-order term, namely, \(\epsilon-\epsilon^{\prime}=\epsilon \epsilon^{\prime}\).
Solution
Step 1 of 3
The normal strain in the reference to the final length is given as,
Here, is the final length and
is the initial length.
The normal strain in the reference to the initial length is given as,
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Title
Mechanics of Materials 10
Author
Russell C. Hibbeler
ISBN
9780134319650