Helium gas with a volume of 2.60 L, under a pressure of 0.180 atm and at a temperature of 41.0°C, is warmed until both pressure and volume are doubled. (a) What is the final temperature? (b) How many grams of helium are there? The molar mass of helium is 4.00 g/mol.

Solution to 2E Step 1 5 Pressure of helium =0.18atm=0.18x10 Pa 3 Volume of helium =2.6L=0.0026m Temperature of helium=41 C 0 Molar mass of helium =4g/mol Step 2 The pressure and volume is doubled, keeping number of moles constant thus, (a)Final Temperature=T 2 P v P V 1 1 = 2 2 T 1 T 2 T2(T 1 2 /2 1 )1 T2(T 1 21 )/1 V1 1 T24T 1 T24x314K=1256K