Air drop A plane traveling horizontally at 80 m/s over

Chapter 8, Problem 84E

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QUESTION:

A plane traveling horizontally at 80 m/s over flat ground at an elevation of 3000 m releases an emergency packet. The trajectory of the packet is given by

\(x=80t,\ y=-4.9t^2+3000,\ \ \ \text{for} t\ \geq\ 0\),

where the origin is the point on the ground directly beneath the plane at the moment of the release. Graph the trajectory of the packet and find the coordinates of the point where the packet lands.

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QUESTION:

A plane traveling horizontally at 80 m/s over flat ground at an elevation of 3000 m releases an emergency packet. The trajectory of the packet is given by

\(x=80t,\ y=-4.9t^2+3000,\ \ \ \text{for} t\ \geq\ 0\),

where the origin is the point on the ground directly beneath the plane at the moment of the release. Graph the trajectory of the packet and find the coordinates of the point where the packet lands.

ANSWER:

Solution 84EStep 1:The trajectory of the packet is gives as Graph of the trajectory of the packet is :

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