Solution Found!
Let X1 and X2 have independent gamma distributions with
Chapter 5, Problem 6E(choose chapter or problem)
Let \(X_{1}\) and \(X_{2}\) have independent gamma distributions with parameters \(\alpha, \theta\) and \(\beta, \theta\), respectively. Let \(W=X_{1} /\left(X_{1}+X_{2}\right)\). Use a method similar to that given in the derivation of the \(F\) distribution (Example 5.2-4) to show that the pdf of \(W\) is
\(g(w)=\frac{\Gamma(\alpha+\beta)}{\Gamma(\alpha) \Gamma(\beta)} w^{\alpha-1}(1-w)^{\beta-1}, \quad 0<w<1\).
We say that W has a beta distribution with parameters \(\alpha\) and \(\beta\). (See Example 5.2-3.)
Equation Transcription:
Text Transcription:
X_1
X_2
Alpha, theta
Beta, theta
W=X_1/(X_1+X_2)
F
W
g(w)=gamma(alpha+beta)/gamma (alpha) gamma(beta)w^-1(1-w)^ beta-1, 0<w<1
Alpha
beta
Questions & Answers
QUESTION:
Let \(X_{1}\) and \(X_{2}\) have independent gamma distributions with parameters \(\alpha, \theta\) and \(\beta, \theta\), respectively. Let \(W=X_{1} /\left(X_{1}+X_{2}\right)\). Use a method similar to that given in the derivation of the \(F\) distribution (Example 5.2-4) to show that the pdf of \(W\) is
\(g(w)=\frac{\Gamma(\alpha+\beta)}{\Gamma(\alpha) \Gamma(\beta)} w^{\alpha-1}(1-w)^{\beta-1}, \quad 0<w<1\).
We say that W has a beta distribution with parameters \(\alpha\) and \(\beta\). (See Example 5.2-3.)
Equation Transcription:
Text Transcription:
X_1
X_2
Alpha, theta
Beta, theta
W=X_1/(X_1+X_2)
F
W
g(w)=gamma(alpha+beta)/gamma (alpha) gamma(beta)w^-1(1-w)^ beta-1, 0<w<1
Alpha
beta
ANSWER:
Step 1 of 4
Given:
and have independent gamma distributions.