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Calculate the change in entropy that occurs when 18.02 g

Chapter 10, Problem 10.37

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QUESTION:

Entropy has been described as “time’s arrow.” Interpret this view of entropy.

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QUESTION:

Entropy has been described as “time’s arrow.” Interpret this view of entropy.

ANSWER:

Step 1 of 4

 

The heat that is used to heat up the ice, melt it, and heat up the resulting liquid will come from the warm water.

Let's calculate the molar amount of each source of water.

\((18.02 g)\left(\frac{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{18.02 \mathrm{~g}}\right)=1.000 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}\)

\((54.05 g)\left(\frac{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{18.02 g}\right)=3.000 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}\)

 

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