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(a) Given a 48.0-V battery and 24.0-? and 96.0-?

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 6PE Chapter 21

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 6PE

(a) Given a 48.0-V battery and 24.0-Ω and 96.0-Ω resistors, find the current and power for each when connected in series. (b) Repeat when the resistances are in parallel.

Step-by-Step Solution:
Step 1 of 3

Solution  6PE

V  =  IR

            48 V    =  I(12Ω)

            I  =  48 /  12

            I  = 0.4 A

   

     P  = \I2 R

 ...

Step 2 of 3

Chapter 21, Problem 6PE is Solved
Step 3 of 3

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

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(a) Given a 48.0-V battery and 24.0-? and 96.0-?

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