itial-value problem.

Chapter 2, Problem 26E

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QUESTION:

In Problems 21–26 solve the given initial-value problem.

\(\left(\frac{1}{1+y^{2}}+\cos x-2 x y\right) \frac{d y}{d x}=y(y+\sin x)\),        y(0)=1

Text Transcription:

(1/1 + y^2 + cos x - 2xy) dy/dx = y(y + sin x)

Questions & Answers

QUESTION:

In Problems 21–26 solve the given initial-value problem.

\(\left(\frac{1}{1+y^{2}}+\cos x-2 x y\right) \frac{d y}{d x}=y(y+\sin x)\),        y(0)=1

Text Transcription:

(1/1 + y^2 + cos x - 2xy) dy/dx = y(y + sin x)

ANSWER:

Step 1 of 3

In this problem we have to solve the given initial value problem,

,  .

 

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