Explain why proposed solutions of radical equations mustbe
Chapter 7, Problem 96(choose chapter or problem)
Explain why proposed solutions of radical equations mustbe checked.ExampleFor Exercises 97 through 100, see the example below.Solve 1t2 - 3t2 - 22t2 - 3t = 0.SolutionSubstitution can be used to make this problem somewhat simpler.Since t2 - 3t occurs more than once, let x = t2 - 3t.1t2 - 3t2 - 22t2 - 3t = 0x - 22x = 0x = 22xx2 = 122x22x2 = 4xx2 - 4x = 0x1x - 42 = 0x = 0 or x - 4 = 0x = 4Now we undo the substitution.x = 0 Replace x with t2 - 3t.t2 - 3t = 0t1t - 32 = 0t = 0 or t - 3 = 0t = 3x = 4 Replace x with t2 - 3t.t2 - 3t = 4t2 - 3t - 4 = 01t - 421t + 12 = 0t - 4 = 0 or t + 1 = 0t = 4 t = -1
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