Solution Found!
Suppose that Y1 and Y2 are binomial random variables with
Chapter 4, Problem 135E(choose chapter or problem)
Suppose that \(Y_{1}\) and \(Y_{2}\) are binomial random variables with parameters \(\left(n, p_{1}\right)\) and \(\left(n, p_{2}\right)\), respectively, where \(p_{1}<p_{2}\). (Note that the parameter is the same for the two variables.)
a Use the binomial formula to deduce that \(P\left(Y_{1}=0\right)>P\left(Y_{2}=0\right)\).
b Use the relationship between the beta distribution function and sums of binomial probabilities given in Exercise 4.134 to deduce that, if is an integer between 1 and \(n-1\),
\(P\left(Y_{1} \leq k\right)=\sum_{i=0}^{k}\left(\begin{array}{l}
n \\
i
\end{array}\right)\left(p_{1}\right)^{i}\left(1-p_{1}\right)^{n-i}=\int_{p_{1}}^{1} \frac{t^{k}(1-t)^{n-k-1}}{B(k+1, n-k)} d t
\).
c If is an integer between 1 and \(n-1\), the same argument used in part (b) yields that
\(P\left(Y_2\le k\right)=\sum_{i=0}^k\left(\begin{array}{l}n\\
i\end{array}\right)\left(p_2\right)^i\left(1-p_2\right)^{n-i}=\int_{p_2}^1\frac{t^k(1-t)^{n-k-1}}{B(k+1,\ n-k)}dt.
\)
Show that, if is any integer between 1 and \(n-1\), \(P\left(Y_{1} \leq k\right)>P\left(Y_{2} \leq k\right)\). Interpret this result.
Equation Transcription:
Text Transcription:
Y_1
Y_2
(n,p_1)
(n,p_2)
p_1<p_2
P(Y_1=0)>P(Y_2=0)
n-1
P(Y_1</=k)=sum i=0 k(_i^n)(p_1)^i(1-p_1)^n-i=integral p1 to 1 t^k(1-t)^n-k-1 over B(k+1, n-k)dt
n-1
P(Y_</=2k)=sum i=0 k(_i^n)(p_2)^i(1-p_2)^n-i=integral p2 to 1 t^k(1-t)^n-k-1 over B(k+1, n-k)dt
n-1
P(Y_1</=k)>P(Y_2</=k)
Questions & Answers
QUESTION:
Suppose that \(Y_{1}\) and \(Y_{2}\) are binomial random variables with parameters \(\left(n, p_{1}\right)\) and \(\left(n, p_{2}\right)\), respectively, where \(p_{1}<p_{2}\). (Note that the parameter is the same for the two variables.)
a Use the binomial formula to deduce that \(P\left(Y_{1}=0\right)>P\left(Y_{2}=0\right)\).
b Use the relationship between the beta distribution function and sums of binomial probabilities given in Exercise 4.134 to deduce that, if is an integer between 1 and \(n-1\),
\(P\left(Y_{1} \leq k\right)=\sum_{i=0}^{k}\left(\begin{array}{l}
n \\
i
\end{array}\right)\left(p_{1}\right)^{i}\left(1-p_{1}\right)^{n-i}=\int_{p_{1}}^{1} \frac{t^{k}(1-t)^{n-k-1}}{B(k+1, n-k)} d t
\).
c If is an integer between 1 and \(n-1\), the same argument used in part (b) yields that
\(P\left(Y_2\le k\right)=\sum_{i=0}^k\left(\begin{array}{l}n\\
i\end{array}\right)\left(p_2\right)^i\left(1-p_2\right)^{n-i}=\int_{p_2}^1\frac{t^k(1-t)^{n-k-1}}{B(k+1,\ n-k)}dt.
\)
Show that, if is any integer between 1 and \(n-1\), \(P\left(Y_{1} \leq k\right)>P\left(Y_{2} \leq k\right)\). Interpret this result.
Equation Transcription:
Text Transcription:
Y_1
Y_2
(n,p_1)
(n,p_2)
p_1<p_2
P(Y_1=0)>P(Y_2=0)
n-1
P(Y_1</=k)=sum i=0 k(_i^n)(p_1)^i(1-p_1)^n-i=integral p1 to 1 t^k(1-t)^n-k-1 over B(k+1, n-k)dt
n-1
P(Y_</=2k)=sum i=0 k(_i^n)(p_2)^i(1-p_2)^n-i=integral p2 to 1 t^k(1-t)^n-k-1 over B(k+1, n-k)dt
n-1
P(Y_1</=k)>P(Y_2</=k)
ANSWER:
Solution:
Step 1 of 4:
Let Y1 and Y2 are binomial random variable with parameters (n, ) and (n, ), respectively, where p1<p2.
We have to show that
- P(Y1=0)>P(Y2=0) by using the binomial formula.
- P(Y1= , by using the relationship between beta distribution function and sums of binomial probabilities, if k is an integer between 1 and n-1.
- P(Y1>P(Y2. If k is any integer between 1 and n-1.