If Y has a log-normal distribution with parameters ? and ?

Chapter 4, Problem 183SE

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QUESTION:

If Y has a log-normal distribution with parameters \(\mu\) and \(\sigma^{2}\), it can be shown that

                      \(E(Y)=e^{\left(\mu+\sigma^{2}\right) / 2} \quad \text { and } \quad V(Y)=e^{2 \mu+\sigma^{2}}\left(e^{\sigma^{2}}-1\right)\).

The grains composing polycrystalline metals tend to have weights that follow a log-normal

distribution. For a type of aluminum, gram weights have a log-normal distribution with \(\mu=3\) and \(\sigma=4\) (in units of \(10^{-2}\) g).

a Find the mean and variance of the grain weights.

b Find an interval in which at least 75% of the grain weights should lie. [Hint: Use Tchebysheff’s theorem.]

c Find the probability that a randomly chosen grain weighs less than the mean grain weight.

Equation Transcription:

Text Transcription:

mu and sigma^2

E(Y)=e(mu+sigma^2)/2 and V(Y)=e^2mu+sigma^2(e^sigma^2-1)

mu=3

sigma=4

10^-2

Questions & Answers

QUESTION:

If Y has a log-normal distribution with parameters \(\mu\) and \(\sigma^{2}\), it can be shown that

                      \(E(Y)=e^{\left(\mu+\sigma^{2}\right) / 2} \quad \text { and } \quad V(Y)=e^{2 \mu+\sigma^{2}}\left(e^{\sigma^{2}}-1\right)\).

The grains composing polycrystalline metals tend to have weights that follow a log-normal

distribution. For a type of aluminum, gram weights have a log-normal distribution with \(\mu=3\) and \(\sigma=4\) (in units of \(10^{-2}\) g).

a Find the mean and variance of the grain weights.

b Find an interval in which at least 75% of the grain weights should lie. [Hint: Use Tchebysheff’s theorem.]

c Find the probability that a randomly chosen grain weighs less than the mean grain weight.

Equation Transcription:

Text Transcription:

mu and sigma^2

E(Y)=e(mu+sigma^2)/2 and V(Y)=e^2mu+sigma^2(e^sigma^2-1)

mu=3

sigma=4

10^-2

ANSWER:

Solution:

Step 1 of 4:

It is given that Y denotes the grain weights and it has the Log-normal distribution with =3,

=4.

Also, it is given that E(Y)= and V(Y)=.

Using this, we need to find the required values.


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