Suppose that Y1 is the total time between a customer’s

Chapter 5, Problem 33E

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

Suppose that \(Y_{1}\) is the total time between a customer’s arrival in the store and departure from the service window, \(Y_{2}\) is the time spent in line before reaching the window, and the joint density of these variables (as was given in Exercise 5.15) is

                             \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

e^{-y_{1}}, & 0 \leq y_{2} \leq y_{1} \leq \infty, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

a Find the marginal density functions for \(Y_{1}\) and \(Y_{2}\).

b What is the conditional density function of \(Y_{1}\) given that \(Y_{2}=y_{2}\)? Be sure to specify the values of \(y_{2}\) for which this conditional density is defined.

c What is the conditional density function of \(Y_{2}\) given that \(Y_{1}=y_{1}\)? Be sure to specify the values of \(y_{1}\) for which this conditional density is defined.

d Is the conditional density function \(f\left(y_{1} \mid y_{2}\right)\) that you obtained in part (b) the same as the marginal density function \(f_{1}\left(y_{1}\right)\) found in part (a)?

e What does your answer to part (d) imply about marginal and conditional probabilities that

\(Y_{1}\) falls in any interval?

Equation Transcription:

Text Transcription:

Y_1

Y_2

f(y_1,y_2)=

e^-y_1, 0</=y_2</=y_1</=infinity,

0, elsewhere.

Y_1

Y_2

Y_1

Y_2=y_2

y_2

Y_2

Y_1=y_1

y_1

f(y_1|y_2)

f_1(y_1)

Y_1

Questions & Answers

QUESTION:

Suppose that \(Y_{1}\) is the total time between a customer’s arrival in the store and departure from the service window, \(Y_{2}\) is the time spent in line before reaching the window, and the joint density of these variables (as was given in Exercise 5.15) is

                             \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

e^{-y_{1}}, & 0 \leq y_{2} \leq y_{1} \leq \infty, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

a Find the marginal density functions for \(Y_{1}\) and \(Y_{2}\).

b What is the conditional density function of \(Y_{1}\) given that \(Y_{2}=y_{2}\)? Be sure to specify the values of \(y_{2}\) for which this conditional density is defined.

c What is the conditional density function of \(Y_{2}\) given that \(Y_{1}=y_{1}\)? Be sure to specify the values of \(y_{1}\) for which this conditional density is defined.

d Is the conditional density function \(f\left(y_{1} \mid y_{2}\right)\) that you obtained in part (b) the same as the marginal density function \(f_{1}\left(y_{1}\right)\) found in part (a)?

e What does your answer to part (d) imply about marginal and conditional probabilities that

\(Y_{1}\) falls in any interval?

Equation Transcription:

Text Transcription:

Y_1

Y_2

f(y_1,y_2)=

e^-y_1, 0</=y_2</=y_1</=infinity,

0, elsewhere.

Y_1

Y_2

Y_1

Y_2=y_2

y_2

Y_2

Y_1=y_1

y_1

f(y_1|y_2)

f_1(y_1)

Y_1

ANSWER:

Solution :

Step 1 of 5:

Let and have joint density function.

Then the joint density function and  is

Our goal is:

a). We need to find the marginal density function of and .

b). We need to find the conditional function of and .

c). We need to is it the conditional function that we obtained in part (b) the same as the

     same same as the marginal density function found in part (a).

d). We need to find what does your to part (d) imply about marginal and conditional probability

      that falls in any interval.

a).

Now we have to find the marginal density function of and .

The marginal density function of a continuous random variable is

or

For is

Therefore,  .

And  is

Therefore,  .


Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back