The times that a cashier spends processing individual

Chapter 7, Problem 62E

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QUESTION:

Problem 62E

The times that a cashier spends processing individual customer’s order are independent random variables with mean 2.5 minutes and standard deviation 2 minutes. What is the approximate probability that it will take more than 4 hours to process the orders of 100 people?

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QUESTION:

Problem 62E

The times that a cashier spends processing individual customer’s order are independent random variables with mean 2.5 minutes and standard deviation 2 minutes. What is the approximate probability that it will take more than 4 hours to process the orders of 100 people?

ANSWER:

Step 1 of 2

The aim is to find the approximate probability that it will take more than 4hours to process the order of 100 people

Let denotes the time of cashier spends in processing for individual customer’s order.

Given mean is 2.5 min

The standard deviation SD() is 2 min

Because the sample size is large the central limit theorem tells us that  is approximately normally distributed with mean

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