Solution Found!
The times that a cashier spends processing individual
Chapter 7, Problem 62E(choose chapter or problem)
Problem 62E
The times that a cashier spends processing individual customer’s order are independent random variables with mean 2.5 minutes and standard deviation 2 minutes. What is the approximate probability that it will take more than 4 hours to process the orders of 100 people?
Questions & Answers
QUESTION:
Problem 62E
The times that a cashier spends processing individual customer’s order are independent random variables with mean 2.5 minutes and standard deviation 2 minutes. What is the approximate probability that it will take more than 4 hours to process the orders of 100 people?
ANSWER:Step 1 of 2
The aim is to find the approximate probability that it will take more than 4hours to process the order of 100 people
Let denotes the time of cashier spends in processing for individual customer’s order.
Given mean is 2.5 min
The standard deviation SD() is 2 min
Because the sample size is large the central limit theorem tells us that is approximately normally distributed with mean