Solution Found!
Using p ? v ? T DataAmmonia contained in a piston?cylinder
Chapter 3, Problem 29P(choose chapter or problem)
Ammonia contained in a piston-cylinder assembly, initially saturated vapor at \(0^{\circ} \mathrm{F}\), undergoes an isothermal process during which its volume (a) doubles, (b) reduces by a half. For each case, fix the final state by giving the quality or pressure, in \(\mathrm{lbf} / \mathrm{in}^2\), as appropriate. Locate the initial and final states on sketches of the p-v and T-v diagrams.
Questions & Answers
QUESTION:
Ammonia contained in a piston-cylinder assembly, initially saturated vapor at \(0^{\circ} \mathrm{F}\), undergoes an isothermal process during which its volume (a) doubles, (b) reduces by a half. For each case, fix the final state by giving the quality or pressure, in \(\mathrm{lbf} / \mathrm{in}^2\), as appropriate. Locate the initial and final states on sketches of the p-v and T-v diagrams.
ANSWER:Step 1 of 4
We have to locate the initial and final states on sketches of the p-v and T-v diagrams for ammonia contained in a piston−cylinder assembly, initially saturated vapor at 0°F, undergoes an isothermal process during which its volume (a) doubles, (b) reduces by a half.
The initial state of the ammonia is a saturated vapour at and the specific volume
and the initial pressure
can be found by making use of the table A-13
0.5739 m3/ kg
2.0769 bar = 30.12 lbf/in2
The final state of the Ammonia if it undergoes an isothermal process during which volume doubles is
Since it is an isothermal process ,= constant
The volume is being doubled so the pressure is given by
=
= 4.1538 bar
= 60.24 lbf/in2