In an L-R-C series circuit, L = 0.280 H and C = 4.00 mF. | StudySoup

Textbook Solutions for University Physics with Modern Physics (1)

Chapter 31 Problem 31.33

Question

In an L-R-C series circuit, L = 0.280 H and C = 4.00 mF. The voltage amplitude of the source is 120 V. (a) What is the resonance angular frequency of the circuit? (b) When the source operates at the resonance angular frequency, the current amplitude in the circuit is 1.70 A. What is the resistance R of the resistor? (c) At the resonance angular frequency, what are the peak voltages across the inductor, the capacitor, and the resistor?

Solution

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The first step in solving 31 problem number 52 trying to solve the problem we have to refer to the textbook question: In an L-R-C series circuit, L = 0.280 H and C = 4.00 mF. The voltage amplitude of the source is 120 V. (a) What is the resonance angular frequency of the circuit? (b) When the source operates at the resonance angular frequency, the current amplitude in the circuit is 1.70 A. What is the resistance R of the resistor? (c) At the resonance angular frequency, what are the peak voltages across the inductor, the capacitor, and the resistor?
From the textbook chapter Alternating Current you will find a few key concepts needed to solve this.

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Title University Physics with Modern Physics (1) 14 
Author Hugh D. Young Roger A. Freedman
ISBN 9780321973610

In an L-R-C series circuit, L = 0.280 H and C = 4.00 mF.

Chapter 31 textbook questions

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