Solution Found!
A small box of mass m is given a speed of v = 21 4gr at the top of the smooth half
Chapter 14, Problem 14-16(choose chapter or problem)
QUESTION:
A small box of mass m is given a speed of \(v = \sqrt{\frac{1}{4}gr}\) at the top of the smooth half cylinder. Determine the angle \(\theta\) at which the box leaves the cylinder.
Questions & Answers
QUESTION:
A small box of mass m is given a speed of \(v = \sqrt{\frac{1}{4}gr}\) at the top of the smooth half cylinder. Determine the angle \(\theta\) at which the box leaves the cylinder.
ANSWER:
Step 1 of 5
First we will draw the free body diagram as below.