Solution Found!
Circle the member of each pair that is more soluble in water. (a) CH3CH2OCH2CH3 or
Chapter 2, Problem PROBLEM 2-7(choose chapter or problem)
Circle the member of each pair that is more soluble in water.
(a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)
(b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)
(c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NHCH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)
(d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)
Questions & Answers
QUESTION:
Circle the member of each pair that is more soluble in water.
(a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)
(b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)
(c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NHCH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)
(d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)
ANSWER:
Problem PROBLEM 2-7
Circle the member of each pair that is more soluble in water.
Step by step solution
Step 1 of 5
Polar solutes dissolve in polar solvent and non polar solutes dissolve in the non - polar solvents.
Water is a polar solvent. Hence, polar solute and polar solvents are more dissolved in water.
a)
The given compounds are as follows.
Diethyl ether is more polar than n - pentane. Hence, diethyl ether is more soluble in water.
Therefore, 
___________________________________________________________________________