The C O double bond has a dipole moment of about 2.4 D and a bond length of about 1.23 . (a) Calculate the amount of charge separation in this bond. (b) Use this information to evaluate the relative importance of the following two resonance contributors: O C R R C+ R R O (R is a general symbol for a carbon-containing group.)
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Textbook Solutions for Organic Chemistry
Question
Circle the member of each pair that is more soluble in water.
(a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)
(b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)
(c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NHCH}_{3} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)
(d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \text { or } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)
Solution
Problem PROBLEM 2-7
Circle the member of each pair that is more soluble in water.
Step by step solution
Step 1 of 5
Polar solutes dissolve in polar solvent and non polar solutes dissolve in the non - polar solvents.
Water is a polar solvent. Hence, polar solute and polar solvents are more dissolved in water.
a)
The given compounds are as follows.
- Diethyl ether
- n - Pentane
Diethyl ether is more polar than n - pentane. Hence, diethyl ether is more soluble in water.
Therefore, is more soluble in water.
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