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The following reaction is a common synthesis used in the organic chemistry laboratory

Chapter 4, Problem 4-34

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QUESTION:

The following reaction is a common synthesis used in the organic chemistry laboratory course. CH3CH2CH2CH2Br CH3OH (methanol solvent) + CH3O + methoxide ion Br 1-bromobutane bromide ion CH3CH2CH2CH2OCH3 methoxybutane When we double the concentration of methoxide ion (CH3O ), we find that the reaction rate doubles. When we triple the concentration of 1-bromobutane, we find that the reaction rate triples. (a) What is the order of this reaction with respect to 1-bromobutane? What is the order with respect to methoxide ion? Write the rate equation for this reaction. What is the overall order? (b) One lab textbook recommends forming the sodium methoxide in methanol solvent, but before adding 1-bromobutane, it first distills off enough methanol to reduce the mixture to half of its original volume. What difference in rate will we see when we run the reaction (using the same amounts of reagents) in half the volume of solvent?

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QUESTION:

The following reaction is a common synthesis used in the organic chemistry laboratory course. CH3CH2CH2CH2Br CH3OH (methanol solvent) + CH3O + methoxide ion Br 1-bromobutane bromide ion CH3CH2CH2CH2OCH3 methoxybutane When we double the concentration of methoxide ion (CH3O ), we find that the reaction rate doubles. When we triple the concentration of 1-bromobutane, we find that the reaction rate triples. (a) What is the order of this reaction with respect to 1-bromobutane? What is the order with respect to methoxide ion? Write the rate equation for this reaction. What is the overall order? (b) One lab textbook recommends forming the sodium methoxide in methanol solvent, but before adding 1-bromobutane, it first distills off enough methanol to reduce the mixture to half of its original volume. What difference in rate will we see when we run the reaction (using the same amounts of reagents) in half the volume of solvent?

ANSWER:

Step 1 of 3

(a)

1- bromobutane reacts with methoxide ion to form methoxybutane and bromide ion.

The balanced reaction is as follows;

                     

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