If we examine Table 21.1, we find that the methylphenols (cresols) are less acidic than phenol itself. For example, Phenol pKa 9.89 OH 4-Methylphenol pKa 10.17 CH3 OH This behavior is characteristic of phenols bearing electron-releasing groups. Provide an explanation.
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Textbook Solutions for Organic Chemistry
Question
A compound X (C10H14O) dissolves in aqueous sodium hydroxide but is insoluble in aqueous sodium bicarbonate. Compound X reacts with bromine in water to yield a dibromo derivative, C10H12Br2O. The 30004000-cm-1 region of the IR spectrum of X shows a broad peak centered at 3250 cm-1 ; the 680840-cm-1 region shows a strong peak at 830-cm-1 . The 1 H NMR spectrum of X gives the following: singlet at d 1.3 (9H), singlet at d 4.9 (1H), and multiplet at d 7.0 (4H). What is the structure of X?
Solution
The first step in solving 21 problem number 32 trying to solve the problem we have to refer to the textbook question: A compound X (C10H14O) dissolves in aqueous sodium hydroxide but is insoluble in aqueous sodium bicarbonate. Compound X reacts with bromine in water to yield a dibromo derivative, C10H12Br2O. The 30004000-cm-1 region of the IR spectrum of X shows a broad peak centered at 3250 cm-1 ; the 680840-cm-1 region shows a strong peak at 830-cm-1 . The 1 H NMR spectrum of X gives the following: singlet at d 1.3 (9H), singlet at d 4.9 (1H), and multiplet at d 7.0 (4H). What is the structure of X?
From the textbook chapter Phenols and Aryl Halides you will find a few key concepts needed to solve this.
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