Radical chlorination of CH3CH3 forms two minor products X and Y of molecular formula
Chapter 15, Problem 15.78(choose chapter or problem)
Radical chlorination of CH3CH3 forms two minor products X and Y of molecular formula C2H4Cl2. a. Identify the structures of X and Y from the following 1 H NMR data: Compound X: singlet at 3.7 ppm Compound Y: doublet at 2.1 and quartet at 5.9 ppm b. Draw a stepwise mechanism that shows how each product is formed from CH3CH3.
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