Benzyl bromide (C6H5CH2Br) reacts rapidly with CH3OH to afford benzyl methyl ether
Chapter 18, Problem 18.59(choose chapter or problem)
Benzyl bromide (C6H5CH2Br) reacts rapidly with CH3OH to afford benzyl methyl ether (C6H5CH2OCH3). Draw a stepwise mechanism for the reaction, and explain why this 1 alkyl halide reacts rapidly with a weak nucleophile under conditions that favor an SN1 mechanism. Would you expect the para-substituted benzylic halides CH3OC6H4CH2Br and O2NC6H4CH2Br to each be more or less reactive than benzyl bromide in this reaction? Explain your reasoning.
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer