Problem 76E

A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing.

a. How many different combinations of 3 cans could be selected?

b. What is the probability that the contaminated can is selected for testing?

Solution:

Step 1 of 2:

Given data states that, the total number of 24 cans 1 can that is contaminated. Three cans are to be chosen randomly for testing.

a). We have to find how many different combinations of 3 cans could be selected.

Given total number of cans = 24

From 24 cans 3 cans could be selected.

Thus, the required combinations are

= 2024

Therefore, 2024 different combinations of 3 cans could be selected.