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Basic Statistics for Business and Economics | 7th Edition | ISBN: 9780077384470 | Authors: Douglas Lind; William Marchal; Samuel Wathen
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A case of 24 cans contains 1 can that is contaminated.

Chapter 5, Problem 76E

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QUESTION:

Problem 76E

A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing.

a. How many different combinations of 3 cans could be selected?

b. What is the probability that the contaminated can is selected for testing?

Questions & Answers

QUESTION:

Problem 76E

A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing.

a. How many different combinations of 3 cans could be selected?

b. What is the probability that the contaminated can is selected for testing?

ANSWER:

 Solution:

Step 1 of 2:

           Given data states that, the total number of 24 cans 1 can that is contaminated. Three cans are to be chosen randomly for testing.

a). We have to find how many different combinations of 3 cans could be selected.

 

          Given total number of cans = 24

                    From 24 cans 3 cans could be selected.

         Thus, the required combinations are

                   

                     = 2024

      Therefore, 2024 different combinations of 3 cans could be selected.

 

 

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