Given the information thatFe3+ + y4- ~ FeY- K, = 1.0 X 10"Cu" + y4- ~ CuY'- K, = 6.3 X

Chapter 14, Problem 14-20

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Given the information thatFe3+ + y4- ~ FeY- K, = 1.0 X 10"Cu" + y4- ~ CuY'- K, = 6.3 X 1018and the further information that, among the several reactants and products,only Cuy2- absorbs radiation at 750 nm, describe how Cu(II) could be usedas an indicator for the photometric titration of Fe(III) with H, Y 2 Reaction:Fe3+ + H,y2- -> FeY + 21r.

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