Solution Found!
Solution: In Exercise, use the following information. On a
Chapter , Problem 47E(choose chapter or problem)
In Exercises 45–50, use the following information. On a dry surface, the braking distances (in feet), from 60 miles per hour to a complete stop, of a sedan can be approximated by a normal distribution, as shown in the figure at the left. (Adapted from Consumer Reports)
What braking distance of a sedan represents the 95th percentile?
Equation Transcription:
Text Transcription:
mu=127 ft
sigma=3.81 ft
Questions & Answers
QUESTION:
In Exercises 45–50, use the following information. On a dry surface, the braking distances (in feet), from 60 miles per hour to a complete stop, of a sedan can be approximated by a normal distribution, as shown in the figure at the left. (Adapted from Consumer Reports)
What braking distance of a sedan represents the 95th percentile?
Equation Transcription:
Text Transcription:
mu=127 ft
sigma=3.81 ft
ANSWER:
Solution:
Step 1 of 2:
We have = 127 ft, = 3.81 ft, and z = 1.2.
The claim is to find the braking distance of a sedan that represents the 95th percentile.