The square surface shown in Fig. 23-30 measures 3.2 mm on each side. It is immersed in a uniform electric field with magnitude E 1800 N/C and with field lines at an angle of u 35 with a normal to the surface, as shown. Take that normal to be directed outward, as though the surface were one face of a box. Calculate the electric flux through the surface. Normal Figure 23-30 Problem 1.
Read moreTable of Contents
Textbook Solutions for Fundamentals of Physics, Volume 2 (Chapters 21 - 44)
Question
Figure 23-35 shows a closed Gaussian surface in the shape of a cube of edge length 2.00 m,with one corner at x1 5.00 m,y1 4.00 m.The cube lies in a region where the electric field vector is given by with y in meters.What is the net charge contained by the cube? E : 3.00i 4.00y2 j 3.00k N/C, Figure 23-35 11.xyz
Solution
The first step in solving 23 problem number 11 trying to solve the problem we have to refer to the textbook question: Figure 23-35 shows a closed Gaussian surface in the shape of a cube of edge length 2.00 m,with one corner at x1 5.00 m,y1 4.00 m.The cube lies in a region where the electric field vector is given by with y in meters.What is the net charge contained by the cube? E : 3.00i 4.00y2 j 3.00k N/C, Figure 23-35 11.xyz
From the textbook chapter Gauss Law you will find a few key concepts needed to solve this.
Visible to paid subscribers only
Step 3 of 7)Visible to paid subscribers only
full solution