The square surface shown in Fig. 23-30 measures 3.2 mm on each side. It is immersed in a uniform electric field with magnitude E 1800 N/C and with field lines at an angle of u 35 with a normal to the surface, as shown. Take that normal to be directed outward, as though the surface were one face of a box. Calculate the electric flux through the surface. Normal Figure 23-30 Problem 1.
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Textbook Solutions for Fundamentals of Physics, Volume 2 (Chapters 21 - 44)
Question
Water in an irrigation ditch of width w 3.22 m and depth d 1.04 m flows with a speed of 0.207 m/s. The mass flux of the flowing water through an imaginary surface is the product of the waters density (1000 kg/m3 ) and its volume flux through that surface. Find the mass flux through the following imaginary surfaces: (a) a surface of area wd, entirely in the water, perpendicular to the flow; (b) a surface with area 3wd/2, of which wd is in the water, perpendicular to the flow; (c) a surface of area wd/2, entirely in the water, perpendicular to the flow; (d) a surface of area wd, half in the water and half out, perpendicular to the flow; (e) a surface of area wd, entirely in the water,with its normal 34.0 from the direction of flow.
Solution
The first step in solving 23 problem number 79 trying to solve the problem we have to refer to the textbook question: Water in an irrigation ditch of width w 3.22 m and depth d 1.04 m flows with a speed of 0.207 m/s. The mass flux of the flowing water through an imaginary surface is the product of the waters density (1000 kg/m3 ) and its volume flux through that surface. Find the mass flux through the following imaginary surfaces: (a) a surface of area wd, entirely in the water, perpendicular to the flow; (b) a surface with area 3wd/2, of which wd is in the water, perpendicular to the flow; (c) a surface of area wd/2, entirely in the water, perpendicular to the flow; (d) a surface of area wd, half in the water and half out, perpendicular to the flow; (e) a surface of area wd, entirely in the water,with its normal 34.0 from the direction of flow.
From the textbook chapter Gauss Law you will find a few key concepts needed to solve this.
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