The population of a community is known to increase at a rate proportional to the number of people present at time t. If an initial population \(P_{0}\) has doubled in 5 years, how long will it take to triple? To quadruple?
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Textbook Solutions for Advanced Engineering Mathematics
Question
Suppose a small single-stage rocket of total mass m(t) is launched vertically and that the rocket consumes its fuel at a constant rate. If the positive direction is upward and if we take air resistance to be linear, then a differential equation for its velocity v(t) is given by
\(\frac{d v}{d t}+\frac{k-\lambda}{m_{0}-\lambda t} v=-g+\frac{R}{m_{0}-\lambda t}\),
where k is the drag coefficient, \(\lambda\) is the rate at which fuel is consumed, R is the thrust of the rocket, \(m_{0}\) is the total mass of the rocket at \(t=0\), and g is the acceleration due to gravity. See Problem 21 in Exercises 1.3.
(a) Find the velocity v(t) of the rocket if \(m_{0}=200 \mathrm{~kg}\), \(R=2000 \mathrm{~N}, \lambda=1 \mathrm{~kg} / \mathrm{s}, g=9.8 \mathrm{~m} / \mathrm{s}^{2}, k=3 \mathrm{~kg} / \mathrm{s}\), and \(v(0)=0\).
(b) Use \(d s / d t=v\) and the result in part (a) to find the height s(t) of the rocket at time t.
Solution
The first step in solving 2.7 problem number 44 trying to solve the problem we have to refer to the textbook question: Suppose a small single-stage rocket of total mass m(t) is launched vertically and that the rocket consumes its fuel at a constant rate. If the positive direction is upward and if we take air resistance to be linear, then a differential equation for its velocity v(t) is given by\(\frac{d v}{d t}+\frac{k-\lambda}{m_{0}-\lambda t} v=-g+\frac{R}{m_{0}-\lambda t}\),where k is the drag coefficient, \(\lambda\) is the rate at which fuel is consumed, R is the thrust of the rocket, \(m_{0}\) is the total mass of the rocket at \(t=0\), and g is the acceleration due to gravity. See Problem 21 in Exercises 1.3. (a) Find the velocity v(t) of the rocket if \(m_{0}=200 \mathrm{~kg}\), \(R=2000 \mathrm{~N}, \lambda=1 \mathrm{~kg} / \mathrm{s}, g=9.8 \mathrm{~m} / \mathrm{s}^{2}, k=3 \mathrm{~kg} / \mathrm{s}\), and \(v(0)=0\).(b) Use \(d s / d t=v\) and the result in part (a) to find the height s(t) of the rocket at time t.
From the textbook chapter Linear Models you will find a few key concepts needed to solve this.
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