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Boyle's Law Explained: From Compression to Pressure Calculation
Chapter 1, Problem 1.2(b)(choose chapter or problem)
A perfect gas undergoes isothermal compression, which reduces its volume by \(1.80\ \mathrm{dm}^3\). The final pressure and volume of the gas are 1.97 bar and \(2.14\ \mathrm{dm}^3\), respectively. Calculate the original pressure of the gas in (a) bar, (b) Torr.
Questions & Answers
QUESTION:
A perfect gas undergoes isothermal compression, which reduces its volume by \(1.80\ \mathrm{dm}^3\). The final pressure and volume of the gas are 1.97 bar and \(2.14\ \mathrm{dm}^3\), respectively. Calculate the original pressure of the gas in (a) bar, (b) Torr.
ANSWER:Step 1 of 3
According to the Boyel's law , the following equation can be used to calculate the original pressure of a gas.
\(p_{i} V_{i}=p_{f} V_{f}\) .............................(1)
Rearrange the equation (1)
\(p_{i}=\left(\frac{\left(p_{f} V_{f}\right)}{V_{i}}\right)\)
Here,
\(V_{i}\) = Initial volume
\(V_{f}\) = Final volume
\(p_{i}\) = Initial pressure
\(p_{f}\) = Final pressure
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Boyle's Law Explained: From Compression to Pressure Calculation
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Learn the intricacies of Boyle's Law through an example involving isothermal compression of a perfect gas. Watch as we calculate the original pressure using the change in volume and final conditions. This tutorial simplifies complex gas laws for easy comprehension.