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Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg
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The anticancer drug Platinol (Cisplatin), Pt(NH3)2Cl2,

Chapter 1, Problem 99P

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QUESTION:

Problem 99P

The anticancer drug Platinol (Cisplatin), Pt(NH3)2Cl2, reacts with the cancer cell's DNA and interferes with its growth, (a) What is the mass % of platinum (Pt) in Platinol? (b) If Pt costs $ 19/g. how many grams of Platinol can be made for $ 1.00 million (assume that the cost of Pt determines the cost of the drug)?

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QUESTION:

Problem 99P

The anticancer drug Platinol (Cisplatin), Pt(NH3)2Cl2, reacts with the cancer cell's DNA and interferes with its growth, (a) What is the mass % of platinum (Pt) in Platinol? (b) If Pt costs $ 19/g. how many grams of Platinol can be made for $ 1.00 million (assume that the cost of Pt determines the cost of the drug)?

ANSWER:

Solution 99P

Here, we have to calculate the mass % of Platinum in platinol

Step 1 of 2

First, let’s calculate the formula mass of Platinol

Chemical formula  of Platinol= Pt(NH3)2Cl2

atomic mass of Platinum = 1 x 195.1 amu   = 195.1 amu

atomic mass of Nitrogen = 2 x 14.01 amu =  28.02 amu

atomic mass of Hydrogen=6 x 1.008 amu =  6.048 amu

atomic mass of chlorine = 2 x 35.45 amu =  70.90 amu

                                                                        _________

                                                                        300.1 amu

                                                                      ___________

Therefore, formula mass of Platinol is 300.1 amu.

Let’s calculate the mass % of Platinum

Mass % of Platinum = 100%

Mass of Platinum = 195.1 amu

Formula mass of Platinol = 300.1 amu.

Mass % of Platinum =  x 100% = 65.01%

Therefore, 65.01% of Platinum is present in Platinol.

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