Complete and balance each equation. If no reaction occurs,

Solution: Here, we are going to describe a process to prepare 250 mL of a 0.250 M sucrose solution. Also, we are going to describe a process to prepare 350.0 ml of 0.100 M sucrose solution starting with 3.00 L of 1.50 M sucrose solution. Step1: Molarity is defined as the number of moles of the solute(Here sucrose is the solute) in 1 litre of the solution. Mathematically, Number of moles of solute Molarity(M) = -------------------------------------- ------(1) Volume of solution in litres Step2: a) Given, volume of the sucrose solution = 250 mL = 250 / 1000 L = 0.250 L Molarity of the sucrose solution = 0.250 M Now, using the molarity expression, we get, Number of moles of sucrose(C H O ) = v1