Solution Found!
Calculate each of the following quantities in 2.00 moles of H3PO4: a. moles of H b
Chapter 0, Problem 7.5(choose chapter or problem)
Calculate each of the following quantities in 2.00 moles of \(\mathrm{H}_{3} \mathrm{PO}_{4}\):
a. moles of \(\mathrm{H}\)
b. moles of \(\mathrm{O}\)
c. atoms of \(\rm{P}\)
d. atoms of \(\mathrm{O}\)
Questions & Answers
QUESTION:
Calculate each of the following quantities in 2.00 moles of \(\mathrm{H}_{3} \mathrm{PO}_{4}\):
a. moles of \(\mathrm{H}\)
b. moles of \(\mathrm{O}\)
c. atoms of \(\rm{P}\)
d. atoms of \(\mathrm{O}\)
ANSWER:Step 1 of 4
(a)
Let’s calculate the number of moles of \(\mathrm{H}\) in \(\mathrm{H}_{3} \mathrm{PO}_{4}\) .
The molecular formula - \(\mathrm{H}_{3} \mathrm{PO}_{4}\)
Conversion factor - \(\frac{3 \text { moles } \mathrm{H}}{1{\text { mole } \mathrm{H}_{3} \mathrm{PO}_{4}}^{-}}\)
For 2.00 moles of \(\mathrm{H}_{3} \mathrm{PO}_{4}\);
\(2.00 \text { moles of } \mathrm{H}_{3} \mathrm{PO}_{4} \times \frac{3 \text { moles } \mathrm{H}}{1 \text { mole } \mathrm{H}_{3} \mathrm{PO}_{4}}=6.00 \text { moles of } \mathrm{H}\)
Therefore, 6 moles of hydrogen is present in given \(\mathrm{H}_{3} \mathrm{PO}_{4}\)