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Molecular iodine,I2(g),dissociates into iodine atoms at 625 K with a first-order rate
Chapter 20, Problem 14.44(choose chapter or problem)
Molecular iodine,, dissociates into iodine atoms at 625 K with a first-order rate constant of .(a) What is the half-life for this reaction? (b) If you start with 0.050 M at this temperature, how much will remain after 5.12 s assuming that the iodine atoms do not recombine to form ?
Questions & Answers
QUESTION:
Molecular iodine,, dissociates into iodine atoms at 625 K with a first-order rate constant of .(a) What is the half-life for this reaction? (b) If you start with 0.050 M at this temperature, how much will remain after 5.12 s assuming that the iodine atoms do not recombine to form ?
ANSWER:Step 1 of 3
First-order reactions represent reactions where the rate is dependent on one reactant’s concentration. If the reactant concentration is doubled in this reaction, the reaction rate also gets doubled.
The half-life denotes the time needed for the reactant concentration to approach half the value of the initial value. The connection between the half-life and reaction rate constant can be given as:
Where
k represents the rate constant.