Find an equation of variation for the given situation.y varies inversely as the square

College Algebra: Graphs and Models | 5th Edition | ISBN: 9780321783950 | Authors: Marvin L. Bittinger, Judith A. Beecher, David J. Ellenbogen, Judith A. Penna

ISBN: 9780321783950 371

Solution for problem 25 Chapter 2.6

College Algebra: Graphs and Models | 5th Edition

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College Algebra: Graphs and Models | 5th Edition

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Problem 25

Find an equation of variation for the given situation.y varies inversely as the square of x, and y = 0.15when x = 0.1

Step-by-Step Solution:

Step 1 of 3

o -= .2 o  o z .10  the RBA up to here is .4000 = 1.28 o confidence interval is -1.29 ≤ z ≤ 1.28 - We want to derive the 1-confidence interval for �� based on a SRS of n elements with n≥30 o = confidence level = given o by definition z we are 1-confident that 1- z ≤ z ≤ z    o thus, we are 1-confident that xx̄ +/- z ��/√n sample error: |xx̄ xx̄ - another description of the CI is this: we areconfident that the sample error |xx̄-does not exceed the margin of error z ��/√n Example: give a 99% confidence interval of th

Step 2 of 3

Chapter 2.6, Problem 25 is Solved

Step 3 of 3

Textbook: College Algebra: Graphs and Models

Edition: 5

Author: Marvin L. Bittinger, Judith A. Beecher, David J. Ellenbogen, Judith A. Penna

ISBN: 9780321783950

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