What is the difference between flow rate and fluid velocity? How are they related?
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Textbook Solutions for College Physics for AP® Courses
Question
The old rubber boot shown in Figure 12.27 has two leaks. To what maximum height can the water squirt from Leak 1? How does the velocity of water emerging from Leak 2 differ from that of leak 1? Explain your responses in terms of energy.
Solution
Step 1 of 2
First we need to calculate the maximum height to which the water can squirt from leak 1.
Water from leak 1 exit to follow the path like a projectile motion from below mentioned formula of projectile for attain a maximum height.
Calculate maximum height of water squirt from leak 1.
\(h=\frac{u^{2} \sin ^{2} \theta}{2 g}\)
Here, h is the maximum height, u is velocity of water at exit of squirt, and \(\theta\) is the angle.
For maximum height water exit at angle of.
Substitute \(45^{\circ}\) for \(\theta\)
\(\begin{array}{l}
h=\frac{u^{2} \sin ^{2} 45^{\circ}}{2 g} \\
=\frac{u^{2}}{2 g}
\end{array}\)
Hence, the maximum height to which water can squirt from leak 1 is
\(\frac{u^{2}}{2 g}\)
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