Answer: The chocolate crumb mystery. This story begins | StudySoup

Textbook Solutions for Fundamentals of Physics

Chapter 26 Problem 60

Question

The chocolate crumb mystery. This story begins with Problem 60 in Chapter 23 and continues through Chapters 24 and 25.The chocolate crumb powder moved to the silo through a pipe of radius R with uniform speed v and uniform charge density r.

(a) Find an expression for the current i (the rate at which charge on the powder moved) through a perpendicular cross section of the pipe.

(b) Evaluate i for the conditions at the factory: pipe radius R = 5.0 cm, speed v = 2.0 m/s, and charge density \(\rho=1.1 \times 10^{-3} \mathrm{C} / \mathrm{m}^{3}\).

If the powder were to flow through a change V in electric potential, its energy could be transferred to a spark at the rate P = iV.

(c) Could there be such a transfer within the pipe due to the radial potential difference discussed in Problem 70 of Chapter 24?

As the powder flowed from the pipe into the silo, the electric potential of the powder changed.The magnitude of that change was at least equal to the radial potential difference within the pipe (as evaluated in Problem 70 of Chapter 24).

(d) Assuming that value for the potential difference and using the current found in (b) above, find the rate at which energy could have been transferred from the powder to a spark as the powder exited the pipe.

(e) If a spark did occur at the exit and lasted for 0.20 s (a reasonable expectation), how much energy would have been transferred to the spark? Recall from Problem 60 in Chapter 23 that a minimum energy transfer of 150 mJ is needed to cause an explosion.

(f) Where did the powder explosion most likely occur: in the powder cloud at the unloading bin (Problem 60 of Chapter 25), within the pipe, or at the exit of the pipe into the silo?

Solution

Step 1 of 7

Given:

Speed of electrons: \(v=2 \mathrm{~m} / \mathrm{s}\)

Radius of the pipe: \(R=5 \mathrm{~cm}=5 \times 10^{-2} \mathrm{~m}\)

Charge density: \(\rho=1.1 \times 10^{-3} \mathrm{C} / \mathrm{m}^{3}\)

We know that charge density is the ratio of total charge to the volume.

\(\begin{aligned}
\rho & =\frac{Q}{V} \\
Q & =\rho \times V
\end{aligned}\)

V is the volume.

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full solution

Title Fundamentals of Physics 10 
Author David Halliday; Robert Resnick; Jearl Walker
ISBN 9781118230725

Answer: The chocolate crumb mystery. This story begins

Chapter 26 textbook questions

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