A 7 Li nucleus with a kinetic energy of 3.00 MeV is sent toward a 232Th nucleus. What is the least center-to-center separation between the two nuclei, assuming that the (more massive) 232Th nucleus does not move?
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Question
(a) Show that the total binding energy Ebe of a given nuclide is Ebe ! Z)H ' N)n # ), where )H is the mass excess of 1 H,)n is the mass excess of a neutron, and ) is the mass excess of the given nuclide. (b) Using this method, calculate the binding energy per nucleon for 197Au. Compare your result with the value listed in Table 42-1. The needed mass excesses, rounded to three significant figures, are )H ! '7.29 MeV, )n ! '8.07 MeV, and )197 ! #31.2 MeV. Note the economy of calculation that results when mass excesses are used in place of the actual masses
Solution
The first step in solving 42 problem number 21 trying to solve the problem we have to refer to the textbook question: (a) Show that the total binding energy Ebe of a given nuclide is Ebe ! Z)H ' N)n # ), where )H is the mass excess of 1 H,)n is the mass excess of a neutron, and ) is the mass excess of the given nuclide. (b) Using this method, calculate the binding energy per nucleon for 197Au. Compare your result with the value listed in Table 42-1. The needed mass excesses, rounded to three significant figures, are )H ! '7.29 MeV, )n ! '8.07 MeV, and )197 ! #31.2 MeV. Note the economy of calculation that results when mass excesses are used in place of the actual masses
From the textbook chapter you will find a few key concepts needed to solve this.
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