Solution Found!
Consider the blocks in Exercise 6.7 as they move 75.0 cm.
Chapter 3, Problem 66P(choose chapter or problem)
Consider the blocks in Exercise 6.7 as they move 75.0 cm. Find the total work done on each one (a) if there is no friction between the table and the 20.0-N block, and (b) if µs = 0.500 and µk = 0.325 between the table and the 20.0-N block. 6.7 . Two blocks are connected by a very light string passing over a massless and frictionless pulley (?Fig. E6.7?). Traveling at constant speed, the 20.0-N block moves 75.0 cm to the right and the 12.0-N block moves 75.0 cm down-ward. How much work is done (a) on the 12.0-N block by (i) gravity and (ii) the tension in the string? (b) How much work is done on the 20.0-N block by (i) gravity, (ii) the tension in the string, (iii) friction, and (iv) the normal force? (c) Find the total work done on each block.
Questions & Answers
QUESTION:
Consider the blocks in Exercise 6.7 as they move 75.0 cm. Find the total work done on each one (a) if there is no friction between the table and the 20.0-N block, and (b) if µs = 0.500 and µk = 0.325 between the table and the 20.0-N block. 6.7 . Two blocks are connected by a very light string passing over a massless and frictionless pulley (?Fig. E6.7?). Traveling at constant speed, the 20.0-N block moves 75.0 cm to the right and the 12.0-N block moves 75.0 cm down-ward. How much work is done (a) on the 12.0-N block by (i) gravity and (ii) the tension in the string? (b) How much work is done on the 20.0-N block by (i) gravity, (ii) the tension in the string, (iii) friction, and (iv) the normal force? (c) Find the total work done on each block.
ANSWER:Solution 66P a) Without friction: Step 1: The work done by gravity on block 1 is, W = F gravitydisplacement = force × displacement × cos Here gravity is acting vertically downwards and the block is moving horizontally. The angle between them is 90 degree, so the cosine of the angle is zero. Hence the work done is zero.