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# The article “Evaluation of a Ventilation Strategy to

ISBN: 9780321629111 32

## Solution for problem 9E Chapter 9

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Probability and Statistics for Engineers and the Scientists | 9th Edition

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Problem 9E

The article “Evaluation of a Ventilation Strategy to Prevent Barotrauma in Patients at High Risk for Acute Respiratory Distress Syndrome” (New Engl. J. of Med., 1998: 355–358) reported on an experiment in which 120 patients with similar clinical features were randomly divided into a control group and a treatment group, each consisting of 60 patients. The sample mean ICU stay (days) and sample standard deviation for the treatment group were 19.9 and 39.1, respectively, whereas these values for the control group were 13.7 and 15.8. a. Calculate a point estimate for the difference between true average ICU stay for the treatment and control groups. Does this estimate suggest that there is a significant difference between true average stays under the two conditions? b. Answer the question posed in part (a) by carrying out a formal test of hypotheses. Is the result different from what you conjectured in part (a)? c. Does it appear that ICU stay for patients given the ventilation treatment is normally distributed? Explain your reasoning. d. Estimate true average length of stay for patients given the ventilation treatment in a way that conveys information about precision and reliability.

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##### ISBN: 9780321629111

The full step-by-step solution to problem: 9E from chapter: 9 was answered by , our top Statistics solution expert on 05/06/17, 06:21PM. Probability and Statistics for Engineers and the Scientists was written by and is associated to the ISBN: 9780321629111. This full solution covers the following key subjects: patients, treatment, Group, stay, average. This expansive textbook survival guide covers 18 chapters, and 1582 solutions. The answer to “The article “Evaluation of a Ventilation Strategy to Prevent Barotrauma in Patients at High Risk for Acute Respiratory Distress Syndrome” (New Engl. J. of Med., 1998: 355–358) reported on an experiment in which 120 patients with similar clinical features were randomly divided into a control group and a treatment group, each consisting of 60 patients. The sample mean ICU stay (days) and sample standard deviation for the treatment group were 19.9 and 39.1, respectively, whereas these values for the control group were 13.7 and 15.8. a. Calculate a point estimate for the difference between true average ICU stay for the treatment and control groups. Does this estimate suggest that there is a significant difference between true average stays under the two conditions? b. Answer the question posed in part (a) by carrying out a formal test of hypotheses. Is the result different from what you conjectured in part (a)? c. Does it appear that ICU stay for patients given the ventilation treatment is normally distributed? Explain your reasoning. d. Estimate true average length of stay for patients given the ventilation treatment in a way that conveys information about precision and reliability.” is broken down into a number of easy to follow steps, and 191 words. This textbook survival guide was created for the textbook: Probability and Statistics for Engineers and the Scientists, edition: 9. Since the solution to 9E from 9 chapter was answered, more than 399 students have viewed the full step-by-step answer.

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